Solve the system: From the third equation, $v_2 = 2v_1 - 3$. Substitute into the first equation: $3(2v_1 - 3) - 2v_3 = 3 \Rightarrow 6v_1 - 9 - 2v_3 = 3 \Rightarrow 6v_1 - 2v_3 = 12$. From the second equation, $v_3 = 3v_1 - 3$. Substitute into $6v_1 - 2(3v_1 - 3) = 12 \Rightarrow 6v_1 - 6v_1 + 6 = 12 \Rightarrow 6 = 12$, which is impossible. Thus, no solution exists.

Tue, 05 May 2026 14:16:49 +0000

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