Solution: The expression under the square root must satisfy $ 4 - x^2 \geq 0 $, so $ x \in [-2, 2] $. The maximum value of $ \sqrt{4 - x^2} $ is $ 2 $ (at $ x = 0 $), and the minimum is $ 0 $ (at $ x = \pm 2 $). The range is $ \boxed{[0, 2]} $.

Wed, 06 May 2026 11:55:48 +0000

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