and between $(1,1,0)$ and $(1,0,1)$: $\sqrt{(0)^2 + (-1)^2 + (1)^2} = \sqrt{2}$, etc. All edges $\sqrt{2}$. Thus, the fourth vertex is $(0,1,1)$.

Sun, 03 May 2026 23:13:50 +0000

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