#### 1, 31. A rectangle has a length that is twice its width. If the perimeter of the rectangle is 60 units, what is the area of the rectangle?

Sat, 02 May 2026 19:42:27 +0000

**Why This Math Challenge Is More Than Just a Homework Question** Today, a simple geometry problem from algebra feels more relevant than ever—especially as more people engage with visual learning tools on Discover. With math trends absorbing attention across US mobile screens, questions about practical shapes like rectangles are rising. The problem “A rectangle’s length is twice its width, with a perimeter of 60 units—what’s the area?” resonates because it blends everyday intuition with logical problem-solving. It connects to real-world contexts like interior design, construction, and design—areas increasingly shaped by digital tools and visual content. As users explore step-by-step breakdowns, this question invites deeper engagement, supporting long dwell time and meaningful scroll through educational and flexible formats. **Understanding the Length-and-Width Relationship** Mathematically, the key insight lies in compressing the relationship between length and width: if width is \( w \), then length is \( 2w \). This ratio simplifies the classic perimeter formula \( P = 2(l + w) \). Substituting long and short into the formula reveals a clear path: \( P = 2(2w + w) = 2(3w) = 6w \). With a known perimeter of 60 units, solving \( 6w = 60 \) swiftly gives \( w = 10 \). This logical step builds clarity, turning a shape problem into a satisfying puzzle.