Solution: Let $ y = rac{3t}{4 - t^2} $. For $ t > 2 $, denominator $ 4 - t^2 < 0 $, so $ y < 0 $. Rewrite $ y = rac{3t}{-(t^2 - 4)} = -rac{3t}{(t - 2)(t + 2)} $. Let $ t = 2 + \epsilon $, $ \epsilon > 0 $, but instead, analyze $ y $: as $ t o 2^+ $, $ y o -\infty $; as $ t o \infty $, $ y o 0^- $. The minimum value of

Wed, 06 May 2026 01:38:15 +0000

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