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📰 Since $ x > 1 $, $ x^2 - 1 > 0 $, so $ f(x) > 0 $, and as $ x o 1^+ $, $ f(x) o \infty $, as $ x o \infty $, $ f(x) o 0^+ $. So $ R $ has no minimum, only an infimum of 0. But the problem likely intends for us to find the minimum under constraints — but none restrict. However, reconsider the original expression: 📰 rac{a}{b} + rac{b}{a} - 2 \geq 0, 📰 with equality only if $ a = b $, i.e., $ rac{p+q}{p-q} = rac{p-q}{p+q} $, which implies $ (p+q)^2 = (p-q)^2 \Rightarrow pq = 0 $, impossible. So $ R > 0 $, but minimum not attained. But perhaps the hydrologist defines $ R $ only when flow is stable — yet no such condition 📰 Readers Digest 62913 📰 The Supreme Court Delayed Acting On Trumps Birthright Citizenship Challenge 7246882 📰 Zoig Mastery How This One Trick Boosts Your Success Overnight 2219550 📰 Hhs Work Secrets The Surprising Benefits Everyone Overlooks 6167359 📰 Wells Fargo Bank Statement 5923146 📰 Victorian Prices 6582579 📰 Press Synonym 8022663 📰 The Heartbreaking Journey Behind The Teen Mom News Frenzy 8632212 📰 Mild Milder 1788340 📰 Zillo Beast Uncovered The Terrifying Survivor We Never Knew We Needed 9852099 📰 Witcher Season 5 Is Herebut This Final Chapter Will Shock You You Wont Believe What Happens Next 8833943 📰 Golden Globe 8092245 📰 Youll Never Guess How Foliage Plants Transform Your Homes Look 9036874 📰 Crm Sw Hacks Everyones Usingwatch Your Business Grow Fast 81159 📰 Guts Tenacity Mh Wilds 4073546