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To find the area enclosed by the ellipse given by \(4x^2 + 9y^2 = 36\), we first rewrite it in standard form. Divide the entire equation by 36:
\frac{4x^2}{36} + \frac{9y^2}{36} = 1 \implies \frac{x^2}{9} + \frac{y^2}{4} = 1
This represents an ellipse with semi-major axis \(a = 3\) (since \(\sqrt{9} = 3\)) and semi-minor axis \(b = 2\) (since \(\sqrt{4} = 2\)).

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