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📅 May 4, 2026 👤 scraface

May 04, 2026

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🔥 Popular Posts

New area:
\frac{\sqrt{3}}{4} \cdot 8^2 = \frac{\sqrt{3}}{4} \cdot 64 = 16\sqrt{3...
Decrease in area:
36\sqrt{3} - 16\sqrt{3} = 20\sqrt{3}
Thus, the area decreases by $ \boxed{20\sqrt{3}} $.
Question: A triangle has side lengths 13 cm, 14 cm, and 15 cm. Find th...
Use Heron’s formula to compute the area. Semi-perimeter $ s $:
Area $ A $:
= \sqrt{21 \cdot 8 \cdot 42} = \sqrt{7056} = 84 \text{ cm}^2
The shortest altitude corresponds to the longest side, which is 15 cm....

📝 Recent Posts

باستخدام متطابقة الزاوية المزدوجة، $\cos 2z = 1 - 2\sin^2 z$, تصبح الم...
- 2\sin^2 z = \sin z \implies 2\sin^2 z + \sin z - 1 = 0
لنفترض $u = \sin z$, إذن:
2u^2 + u - 1 = 0 \implies u = \frac{-1 \pm \sqrt{1 + 8}}{4} = \frac{-1...
إذن، $u = \frac{1}{2}$ أو $u = -1$.
لـ $\sin z = \frac{1}{2}$:
z = 30^\circ \quad \text{أو} \quad z = 150^\circ
لـ $\sin z = -1$:
z = 270^\circ
وبالتالي، الحلول في $[0^\circ, 360^\circ]$ هي:

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