Thus, \( \frac{25\pi}{144} h^2 \frac{dh}{dt} = -0.2 \sqrt{h} \) → \( \frac{dh}{dt} = -\frac{0.2 \cdot 144}{25\pi} \cdot h^{-3/2} = -\frac{28.8}{25\pi} h^{-3/2} \).

Sun, 03 May 2026 00:42:47 +0000

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