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📰 Alternatively, simpler: add all counts, subtract duplicates not in sum—since 12 are shared in all 5, they are counted 5 times but should be once. So subtract 4×12 = 48 from total sum.
📰 Total distinct = 160 - 48 = <<160-48=112>>112? Wait—this is incorrect because the 12 are shared, so they are counted once in total, but appear 5 times in sum. So subtract 4×12 = 48 → 160 - 48 = 112.
📰 But data shows 32, 28, 36, 30, 34 — if these include the 12 common species, then total distinct = sum of all unique local species minus overlaps. However, the phrasing 12 species common across all suggests they are included in each count, so total distinct = (32–12) + (28–12) + (36–12) + (30–12) + (34–12) + 12 = 20 + 16 + 24 + 18 + 22 + 12 = <<20+16+24+18+22+12=112>>112.
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