Set $ \frac{1}{\sin z \cos z} = 2 $. Then $ \sin z \cos z = \frac{1}{2} $. Using the identity $ \sin(2z) = 2\sin z \cos z $, we get $ \sin(2z) = 1 $. Solve $ \sin(2z) = 1 $:

Wed, 06 May 2026 18:44:40 +0000

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